If it's not what You are looking for type in the equation solver your own equation and let us solve it.
149.4954=3.14r^2
We move all terms to the left:
149.4954-(3.14r^2)=0
We get rid of parentheses
-3.14r^2+149.4954=0
a = -3.14; b = 0; c = +149.4954;
Δ = b2-4ac
Δ = 02-4·(-3.14)·149.4954
Δ = 1877.662224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1877.662224}}{2*-3.14}=\frac{0-\sqrt{1877.662224}}{-6.28} =-\frac{\sqrt{}}{-6.28} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1877.662224}}{2*-3.14}=\frac{0+\sqrt{1877.662224}}{-6.28} =\frac{\sqrt{}}{-6.28} $
| x–2(x+1)+3(x–2)+2(x–6)=0 | | 77+3x+5+3x+50=180 | | 2x^+4=22 | | −6 | | N^2-7n+42=0 | | 7r^2-13r-2=0 | | 5/7x-45=8x+52 | | 2x+3x=84 | | 5x+(x+8)=-16-2x | | 3+5x)/5=(4-X)/7 | | (6x+3)×2=18 | | 40+2x+2x+20=180 | | v^2+12=0 | | v^+12=0 | | (z+1)^2=28 | | Q=5,000,000x(1-0.03) | | 7w^2+63=0 | | 3c^2-18c+26=0 | | 3u^2+12=0 | | 3u^2=12=0 | | 5v^2-10=0 | | 360=4x+6x+7x+7x | | -14+6u+3=8u+19 | | 68+11x+13=180 | | -5+8q=2q+20+11 | | 2x/9=8/36 | | 70+4x+50+x=180 | | 3m-18=6m+18+18 | | -13d+14-12d=19+14 | | 4x+6=12x+3 | | 4x+6=12x=3 | | -10c+19+1=-18-12c |